18=x^2-3x+2/2

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Solution for 18=x^2-3x+2/2 equation: 


x in (-oo:+oo)

18 = x^2-(3*x)+2/2 // - x^2-(3*x)+2/2

3*x-x^2-(2/2)+18 = 0

3*x-x^2-1+18 = 0

3*x-x^2+17 = 0

DELTA = 3^2-(-1*4*17)

DELTA = 77

DELTA > 0

x = (77^(1/2)-3)/(-1*2) or x = (-77^(1/2)-3)/(-1*2)

x = (77^(1/2)-3)/(-2) or x = (77^(1/2)+3)/2

x in { (77^(1/2)-3)/(-2), (77^(1/2)+3)/2 }

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